Match the List-$I$ with List-$II$:
List-$I$ (Reagent) List-$II$ (Functional Group detected)
$A$. Sodium bicarbonate solution $I$. Double bond/unsaturation
$B$. Neutral ferric chloride $II$. Carboxylic acid
$C$. Ceric ammonium nitrate $III$. Phenolic $-OH$
$D$. Alkaline $KMnO_4$ $IV$. Alcoholic $-OH$

Choose the correct answer from the options given below:

  • A
    $A-II, B-III, C-IV, D-I$
  • B
    $A-II, B-III, C-I, D-IV$
  • C
    $A-III, B-II, C-IV, D-I$
  • D
    $A-II, B-IV, C-III, D-I$

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Similar Questions

During the fusion of an organic compound with sodium metal,the nitrogen present in the organic compound is converted into:

Match List-$I$ with List-$II$:
List-$I$ (Test/Reagents/Observation) List-$II$ (Species detected)
$(a)$ Lassaigne's Test $(i)$ Carbon
$(b)$ $Cu(II)$ oxide $(ii)$ Sulphur
$(c)$ Silver nitrate $(iii)$ $N, S, P,$ and halogen
$(d)$ The sodium fusion extract gives black precipitate with acetic acid and lead acetate $(iv)$ Halogen specifically

The correct match is:

Lassaigne's test for nitrogen is negative for which compound?

In the Lassaigne sodium fusion test,$N$ and $S$ of an organic compound are converted into:

Beilstein test is used for the detection of which one of the following elements?

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