Matrix A = begin{bmatrix} x & 3 & 2 1 & y & | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) We know that for any square matrix $A$,the property $A (adj A) = |A| I$ holds,where $I$ is the identity matrix of the same order.First,we calculat

Vedclass · Accepted Answer

$\begin{bmatrix} 68 & 0 & 0 \ 0 & 68 & 0 \ 0 & 0 & 68 \end{bmatrix}$

Vedclass · Answer

(C) We know that for any square matrix $A$,the property $A (adj A) = |A| I$ holds,where $I$ is the identity matrix of the same order.First,we calculate the determinant $|A|$ of the matrix $A = \begin{bmatrix} x & 3 & 2 \ 1 & y & 4 \ 2 & 2 & z \end{bmatrix}$.$|A| = x(yz - 8) - 3(z - 8) + 2(2 - 2y)$$|A| = xyz - 8x - 3z + 24 + 4 - 4y$$|A| = xyz - (8x + 4y + 3z) + 28$Given $xyz = 60$ and $8x + 4y + 3z = 20$,we substitute these values into the expression for $|A|$:$|A| = 60 - 20 + 28 = 68$.Therefore,$A (adj A) = |A| I = 68 I = \begin{bmatrix} 68 & 0 & 0 \ 0 & 68 & 0 \ 0 & 0 & 68 \end{bmatrix}$.

Matrix $A = \begin{bmatrix} x & 3 & 2 \\ 1 & y & 4 \\ 2 & 2 & z \end{bmatrix}$. If $xyz = 60$ and $8x + 4y + 3z = 20$,then $A (adj A)$ is equal to:

Similar Questions

If $A$ is a non-zero square matrix of order $n$ with $\det(I+A) \neq 0$ and $A^3=O$, where $I$ and $O$ are the identity and null matrices of order $n \times n$ respectively, then $(I+A)^{-1}$ is equal to

If possible,using elementary row transformations,find the inverse of the following matrix: $\left[\begin{array}{ccc}2 & 3 & -3 \\ -1 & -2 & 2 \\ 1 & 1 & 1\end{array}\right]$

If $A = \begin{bmatrix} k/2 & 0 & 0 \\ 0 & l/3 & 0 \\ 0 & 0 & m/4 \end{bmatrix}$ and $A^{-1} = \begin{bmatrix} 1/2 & 0 & 0 \\ 0 & 1/3 & 0 \\ 0 & 0 & 1/4 \end{bmatrix}$,then $k+l+m=$

If $P$ is a $3 \times 3$ real matrix such that $P^{T} = aP + (a - 1)I$,where $a > 1$,then $..........$

If $A = \begin{bmatrix} 2 & -3 \\ -4 & 1 \end{bmatrix}$,then $\text{adj}(3A^2 + 12A)$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module