The maximum force of friction is called:

Block $B$ lying on a table weighs $W$. The coefficient of static friction between the block and the table is $\mu$. Assume that the cord between $B$ and the knot is horizontal. The maximum weight of the block $A$ for which the system will be stationary is

$A$ block of mass $2\,kg$ is at rest on a floor. The coefficient of static friction between the block and the floor is $0.54$. $A$ horizontal force of $2.8\,N$ is applied to the block. What will be the frictional force between the block and the floor (in $.8$)? $(g = 10\,m/s^2)$

How does static friction oppose motion? On which factors does the value of the coefficient of friction depend?

Find the minimum value of mass $m$ that should be placed on the $20 \, kg$ block so that the system remains at rest. (Given coefficient of friction $\mu = 0.25$) (in $, kg$)

If ${\mu _s}$,${\mu _k}$,and ${\mu _r}$ are coefficients of static friction,sliding (kinetic) friction,and rolling friction respectively,then: