Maximum number of electrons possible with spi | vedclass

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Question

(A) The total number of electrons in a shell with principal quantum number $n$ is given by $2n^2$. For $n=4$,the total number of electrons is $2 	ime

Vedclass · Accepted Answer

$16$

Vedclass · Answer

(A) The total number of electrons in a shell with principal quantum number $n$ is given by $2n^2$. For $n=4$,the total number of electrons is $2 	imes 4^2 = 32$. Since each orbital can hold a maximum of $2$ electrons with opposite spins ($+\frac{1}{2}$ and $-\frac{1}{2}$),exactly half of the total electrons will have a spin quantum number of $+\frac{1}{2}$. Therefore,the number of electrons with spin $+\frac{1}{2}$ is $\frac{32}{2} = 16$.

Maximum number of electrons possible with spin quantum number $+\frac{1}{2}$ with principal quantum number $n=4$ in an atom is

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