Maximum number of isomers of C_4H_8 are | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The molecular formula $C_4H_8$ has a degree of unsaturation of $1$. This indicates the presence of either one double bond or one ring.The possible

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(D) The molecular formula $C_4H_8$ has a degree of unsaturation of $1$. This indicates the presence of either one double bond or one ring.The possible isomers are:$1.$ $CH_2=CH-CH_2-CH_3$ ($1$-Butene)$2.$ $cis-CH_3-CH=CH-CH_3$ (cis$-2-$Butene)$3.$ $trans-CH_3-CH=CH-CH_3$ (trans$-2-$Butene)$4.$ $CH_2=C(CH_3)_2$ ($2$-Methylpropene)$5.$ Cyclobutane (four-membered ring)$6.$ Methylcyclopropane (three-membered ring)Thus,there are a total of $6$ isomers.

Maximum number of isomers of $C_4H_8$ are

Similar Questions

Which carbocation is the most stable?

Stereochemistry of the product is

Which of the following Fischer projection formulas is the same as $D$-Glyceraldehyde?

Which of the following will not lose asymmetry on reduction with $LiAlH_4$?

Which of the following pairs does not exhibit isomerism?

Vedclass Test Series

Exam Paper Generator

Online Exam Module