The maximum value of f(x) = sin x + cos x is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The given function is $f(x) = \sin x + \cos x$.We can write this in the form $a \sin x + b \cos x$,where $a = 1$ and $b = 1$.The maximum value of

Vedclass · Accepted Answer

$\sqrt{2}$

Vedclass · Answer

(D) The given function is $f(x) = \sin x + \cos x$.We can write this in the form $a \sin x + b \cos x$,where $a = 1$ and $b = 1$.The maximum value of the function $f(x) = a \sin x + b \cos x$ is given by the formula $\sqrt{a^2 + b^2}$.Substituting the values,we get $\sqrt{1^2 + 1^2} = \sqrt{1 + 1} = \sqrt{2}$.Therefore,the maximum value is $\sqrt{2}$.

The maximum value of $f(x) = \sin x + \cos x$ is

Similar Questions

The value of $\sqrt{3} \operatorname{cosec} 20^{\circ} - \sec 20^{\circ} = $

The value of $\frac{1}{4} \tan \frac{\pi}{8} + \frac{1}{8} \tan \frac{\pi}{16} + \frac{1}{16} \tan \frac{\pi}{32} + \dots \infty$ terms is equal to-

If $A + B = \frac{\pi}{4}$,then $(1 + \tan A)(1 + \tan B) = $

Let $f(x) = \max (\sin x, \cos x)$ and $g(x) = \min (\cos x, \sin x)$. If the equation $f(x)y^2 + ay + g(x) = 0$ has real roots for all $x \in R$,then the complete set of values of $a$ is:

$cosec^2 \theta = \frac{4xy}{(x + y)^2}$ is true if and only if

Vedclass Test Series

Exam Paper Generator

Online Exam Module