The maximum value of static friction is called:

The maximum static frictional force is

The coefficient of static friction between a wooden block of mass $0.5\, kg$ and a vertical rough wall is $0.2$. The magnitude of the horizontal force that should be applied on the block to keep it adhered to the wall will be $N$ $\left[ g = 10\, m/s^2 \right]$.

$A$ block of mass $1 \, kg$ is at rest on a horizontal table. The coefficient of static friction between the block and the table is $0.5$. The magnitude of the force acting upwards at an angle of $60^{\circ}$ from the horizontal that will just start the block moving is

$A$ body of mass $4\, kg$ is at rest on a horizontal table. The coefficient of friction between the body and the table is $0.2$. $A$ horizontal force of $6\, N$ is applied on the body. The acceleration of the body is .......... $m/s^2$.

$A$ block of mass $m$ rests on a horizontal table with a coefficient of static friction $\mu$. What minimum force must be applied on the block to drag it on the table?