Mayank made a bird-bath for his garden in the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let $h$ be the height of the cylinder and $r$ be the common radius of the cylinder and the hemisphere.Given: $h = 1.45\, m = 145\, cm$ and $r = 30

Vedclass · Accepted Answer

$3.3$

Vedclass · Answer

(D) Let $h$ be the height of the cylinder and $r$ be the common radius of the cylinder and the hemisphere.Given: $h = 1.45\, m = 145\, cm$ and $r = 30\, cm$.The total surface area of the bird-bath is the sum of the curved surface area of the cylinder and the curved surface area of the hemisphere.Total Surface Area $= 	ext{CSA of cylinder} + 	ext{CSA of hemisphere}$$= 2\pi rh + 2\pi r^2 = 2\pi r(h + r)$$= 2 	imes \frac{22}{7} 	imes 30 	imes (145 + 30)\, cm^2$$= 2 	imes \frac{22}{7} 	imes 30 	imes 175\, cm^2$$= 2 	imes 22 	imes 30 	imes 25\, cm^2$$= 33000\, cm^2$Since $1\, m^2 = 10000\, cm^2$,we have:Total Surface Area $= \frac{33000}{10000}\, m^2 = 3.3\, m^2$.

Mayank made a bird-bath for his garden in the shape of a cylinder with a hemispherical depression at one end (see figure). The height of the cylinder is $1.45\, m$ and its radius is $30\, cm$. Find the total surface area of the bird-bath in $m^2$. (Take $\pi = \frac{22}{7}$)

Similar Questions

$2$ cubes each of volume $64 \, cm^3$ are joined end to end. Find the surface area of the resulting cuboid in $cm^2$.

The radius and height of a cone are $5\,cm$ and $12\,cm$ respectively. Then,the ratio of its $CSA$ and area of base is $\ldots \ldots \ldots \ldots$

Total surface area of a cylinder with radius $7 \, cm$ and height $13 \, cm$ is $\ldots \ldots \ldots \ldots \, cm^{2}$.

The area of the base of a cylinder is $616\,cm^{2}$. Then,the radius of the base of the cylinder is $\ldots \ldots \ldots \ldots cm.$

$A$ surahi is the combination of

Vedclass Test Series

Exam Paper Generator

Online Exam Module