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(B) The internal volume of the rectangular box is calculated as: $V_{	ext{box}} = 16 \, cm 	imes 8 \, cm 	imes 8 \, cm = 1024 \, cm^3$.The volume o

Vedclass · Accepted Answer

$488$

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(B) The internal volume of the rectangular box is calculated as: $V_{	ext{box}} = 16 \, cm 	imes 8 \, cm 	imes 8 \, cm = 1024 \, cm^3$.The volume of a single sphere with radius $r = 2 \, cm$ is given by the formula $V_{	ext{sphere}} = \frac{4}{3} \pi r^3$.Substituting the values: $V_{	ext{sphere}} = \frac{4}{3} 	imes 3.14 	imes (2)^3 = \frac{4}{3} 	imes 3.14 	imes 8 = \frac{100.48}{3} \approx 33.4933 \, cm^3$.The total volume occupied by $16$ such spheres is: $V_{	ext{total spheres}} = 16 	imes 33.4933 = 535.8933 \, cm^3$.The volume of the preservative liquid is the remaining space in the box: $V_{	ext{liquid}} = V_{	ext{box}} - V_{	ext{total spheres}} = 1024 - 535.8933 = 488.1067 \, cm^3$.Rounding to the nearest integer,we get $488 \, cm^3$.

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