Michaelis constant K_m is equal to: | vedclass

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Question

(B) In the Michaelis-Menten enzyme kinetics model,the reaction is represented as $E+S \underset{K_2}{\stackrel{K_1}{\rightleftharpoons}} E S \xrightar

Vedclass · Accepted Answer

$\frac{K_2 + K_3}{K_1}$

Vedclass · Answer

(B) In the Michaelis-Menten enzyme kinetics model,the reaction is represented as $E+S \underset{K_2}{\stackrel{K_1}{\rightleftharpoons}} E S \xrightarrow{K_3} E+P$
Here,$K_1$ is the rate constant for the formation of the enzyme-substrate complex,$K_2$ is the rate constant for the dissociation of the complex back into enzyme and substrate,and $K_3$ (often denoted as $k_{cat}$) is the rate constant for the formation of the product.
The Michaelis constant $K_m$ is defined as the substrate concentration at which the reaction rate is half of the maximum velocity $(V_{max})$.
Mathematically,it is expressed as $K_m = \frac{K_2 + K_3}{K_1}$.

Column $I$	Column $II$
$i$. Purely proteinaceous enzyme	$a$. Glucokinase
$ii$. Conjugated enzyme	$b$. Epimerase
$iii$. Transferase enzyme	$c$. Protease
$iv$. Isomerase enzyme	$d$. $FMN$

Michaelis constant $K_m$ is equal to:

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The following reaction depicts the activity of a particular class of enzymes:
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Column $I$ Column $II$
$i$. Purely proteinaceous enzyme $a$. Glucokinase
$ii$. Conjugated enzyme $b$. Epimerase
$iii$. Transferase enzyme $c$. Protease
$iv$. Isomerase enzyme $d$. $FMN$

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