Molecular bromine on reaction with three mole | vedclass

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Question

(B) Molecular bromine $(Br_2)$ reacts with $3$ moles of molecular fluorine $(F_2)$ to produce $2$ moles of $BrF_3$.$BrF_3$ is an interhalogen compound

Vedclass · Accepted Answer

$2$

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(B) Molecular bromine $(Br_2)$ reacts with $3$ moles of molecular fluorine $(F_2)$ to produce $2$ moles of $BrF_3$.$BrF_3$ is an interhalogen compound.The chemical reaction is:$Br_{2(g)} + 3F_{2(g)} \longrightarrow 2BrF_{3(g)}$In $BrF_3$,the central bromine atom has $7$ valence electrons. It forms $3$ covalent bonds with $3$ fluorine atoms,using $3$ electrons.Remaining electrons = $7 - 3 = 4$ electrons,which form $2$ lone pairs.Thus,the total number of lone pairs at the central bromine atom is $2$.

List-$I$	List-$II$
$A. XeF_4$	$I. See-saw$
$B. SF_4$	$II. Square planar$
$C. NH_4^{+}$	$III. Bent T-shaped$
$D. BrF_3$	$IV. Tetrahedral$

Molecular bromine on reaction with three moles of molecular fluorine produces an interhalogen compound. The total number of lone pairs at the central halogen atom is

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Match List-$I$ with List-$II$:
List-$I$ List-$II$
$A. XeF_4$ $I. See-saw$
$B. SF_4$ $II. Square planar$
$C. NH_4^{+}$ $III. Bent T-shaped$
$D. BrF_3$ $IV. Tetrahedral$

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