Molecular shapes of $SF_4$,$CF_4$ and $XeF_4$ are
- AThe same with $2, 0$ and $1$ lone pairs of electrons respectively
- BThe same,with $1, 1$ and $1$ lone pairs of electrons respectively
- CDifferent,with $0, 1$ and $2$ lone pairs of electrons respectively
- DDifferent,with $1, 0$ and $2$ lone pairs of electrons respectively
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Similar Questions
What is the $\angle HOH$ bond angle in the $H_2O$ molecule?
Match the following molecules/ions in List-$I$ with the number of lone pairs of electrons on the central atom in List-$II$.
List-$I$ (molecule/ion) List-$II$ (Number of lone pairs of electrons on the central atom) $(A)$ $XeF_2$ $(I)$ $2$ $(B)$ $XeO_3$ $(II)$ $0$ $(C)$ $XeF_4$ $(III)$ $3$ $(D)$ $PF_6^-$ $(IV)$ $1$
| List-$I$ (molecule/ion) | List-$II$ (Number of lone pairs of electrons on the central atom) |
|---|---|
| $(A)$ $XeF_2$ | $(I)$ $2$ |
| $(B)$ $XeO_3$ | $(II)$ $0$ |
| $(C)$ $XeF_4$ | $(III)$ $3$ |
| $(D)$ $PF_6^-$ | $(IV)$ $1$ |
The increasing order of the number of lone pairs of electrons on the central atom of the following molecules is:
$I) \ ClF_3$
$II) \ XeF_2$
$III) \ SF_4$
$IV) \ SiH_4$
$I) \ ClF_3$
$II) \ XeF_2$
$III) \ SF_4$
$IV) \ SiH_4$
$H_2O$ is
Medium
View SolutionThe geometries of $XeF_4$ and $XeOF_4$ respectively are
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