Monochlorination of toluene in the presence o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Halogenation in the presence of light follows a free radical pathway and reacts with the alkyl group to give a haloalkyl compound.The formed haloa

Vedclass · Accepted Answer

benzyl alcohol

Vedclass · Answer

(D) Halogenation in the presence of light follows a free radical pathway and reacts with the alkyl group to give a haloalkyl compound.The formed haloalkyl,in the presence of an alkaline medium,undergoes a nucleophilic substitution reaction where the halogen atom is replaced by a hydroxyl group to form an alcohol.The reaction with toluene can be represented as:$C_6H_5CH_3$ $\xrightarrow{Cl_2, hv} C_6H_5CH_2Cl$ $\xrightarrow{	ext{aq. } NaOH} C_6H_5CH_2OH$Thus,the monochlorination of toluene in sunlight followed by hydrolysis with aqueous $NaOH$ yields benzyl alcohol.

Monochlorination of toluene in the presence of sunlight followed by hydrolysis gives:

Similar Questions

Which is the correct decreasing order of boiling points for the following compounds?

Consider the following bromides. What is the correct order of $S_N1$ reactivity?

$2-$Methylpropyl bromide reacts with $C_2H_5O^-$ to give $A$,whereas on reaction with $C_2H_5OH$ it gives $B$. The mechanism followed in these reactions and the products $A$ and $B$ respectively are:

Identify the correct decreasing order of ease of dehydrohalogenation of alkyl halides.

The correct order of rates of $C-Br$ bond ionisation of the following bromides is

Vedclass Test Series

Exam Paper Generator

Online Exam Module