The IUPAC name of the compound given below is | vedclass

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(B) $1$. Identify the longest carbon chain. The longest chain contains $8$ carbon atoms,so the parent alkane is octane.$2$. Number the chain from the

Vedclass · Accepted Answer

$4-$ethyl$-3-$methyloctane

Vedclass · Answer

(B) $1$. Identify the longest carbon chain. The longest chain contains $8$ carbon atoms,so the parent alkane is octane.$2$. Number the chain from the end that gives the lowest locants to the substituents. Numbering from left to right gives substituents at positions $3$ and $4$.$3$. At position $3$,there is a methyl group $(-CH_3)$,and at position $4$,there is an ethyl group $(-CH_2CH_3)$.$4$. According to $IUPAC$ rules,substituents are listed in alphabetical order: ethyl comes before methyl.$5$. Therefore,the correct name is $4-$ethyl$-3-$methyloctane.

The $IUPAC$ name of the compound given below is:

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