Natural glucose is termed D-glucose because | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In the Fischer projection of monosaccharides,the $D$ or $L$ configuration is determined by the position of the $-OH$ group on the chiral carbon at

Vedclass · Accepted Answer

$-OH$ on the fifth carbon is on the right side in Fischer projection

Vedclass · Answer

(C) In the Fischer projection of monosaccharides,the $D$ or $L$ configuration is determined by the position of the $-OH$ group on the chiral carbon atom furthest from the carbonyl group (the highest numbered chiral carbon).For glucose,the chiral carbon furthest from the aldehyde group is the $C-5$ carbon.In $D$-glucose,the $-OH$ group on the $C-5$ carbon is on the right side in the Fischer projection.Therefore,the correct option is $C$.

Natural glucose is termed $D$-glucose because

Similar Questions

If a monosaccharide contains a keto group,it is known as:

What is the product formed when glucose reacts with an excess of $C_6H_5-NH.NH_2$?

The Haworth projection shown below represents:

The formation of a silver mirror by the reaction of glucose with Tollens' reagent indicates the presence of which group?

Consider the following statements:
Statement $I$: All monosaccharides are reducing sugars.
Statement $II$: Sucrose can reduce ammoniacal silver nitrate solution.
Choose the correct answer from the options given below.

Vedclass Test Series

Exam Paper Generator

Online Exam Module