Negation of "Paris is in France and London is in England" is

$(p \to q) \leftrightarrow (q \vee \sim p)$ is

The statement pattern $p \rightarrow \sim(p \wedge \sim q)$ is equivalent to

If the truth value of the compound statement $[(p \leftrightarrow q) \land (q \to r) \land \sim r] \to (p \land \sim q)$ is false, then the truth values of the statement patterns $(p \to q) \leftrightarrow (q \to r)$ and $\sim (p \lor r) \to (q \land p)$ are, respectively ...

Consider the following statements:
$r: \text{If } p \to q \text{ is false, then } p \lor q \text{ is false.}$
$s: \text{If } p \leftrightarrow q \text{ is false, then } p \lor q \text{ is false.}$
The truth values of $r \to s$ and $s \to r$ are respectively:

The negation of the statement $''96$ is divisible by $2$ and $3''$ is