Nickel combines with a uninegative monodentate ligand $(X^{-})$ to form a paramagnetic complex $[NiX_4]^{2-}$. The hybridisation involved and the number of unpaired electrons present in the complex are respectively:
- A$sp^3$, two
- B$dsp^2$, zero
- C$dsp^2$, one
- D$sp^3$, one
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Similar Questions
Which of the following complex ions does not contain any $d$-electrons in the central metal atom?
Medium
View Solution$[NiCl_{4}]^{2-}$ is paramagnetic while $[Ni(CO)_{4}]$ is diamagnetic though both are tetrahedral. Why?
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View SolutionMatch List-$I$ with List-$II$ and select the correct answer using the codes given below the lists $:$
List-$I$ $(Compounds)$ List-$II$ $(Hybridization)$ $(a)$ $[Ni(NH_3)_6]^{+2}$ $(i)$ $sp^3 d^2$ $(b)$ $[PtCl_4]^{-2}$ $(ii)$ $dsp^2$ $(c)$ $[Ni(CO)_4]$ $(iii)$ $sp^3$ $(d)$ $[Co(OX)_3]^{-3}$ $(iv)$ $d^2 sp^3$
| List-$I$ $(Compounds)$ | List-$II$ $(Hybridization)$ |
| $(a)$ $[Ni(NH_3)_6]^{+2}$ | $(i)$ $sp^3 d^2$ |
| $(b)$ $[PtCl_4]^{-2}$ | $(ii)$ $dsp^2$ |
| $(c)$ $[Ni(CO)_4]$ | $(iii)$ $sp^3$ |
| $(d)$ $[Co(OX)_3]^{-3}$ | $(iv)$ $d^2 sp^3$ |
Medium
View SolutionWhich of the following has the maximum number of unpaired electrons?
Easy
View SolutionIn solid $CuSO_4 \cdot 5H_2O$,copper is coordinated to:
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