Nitrobenzene can be prepared from benzene by | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In the nitration of benzene,the reaction between conc. $HNO_3$ and conc. $H_2SO_4$ occurs as follows: $HNO_3 + H_2SO_4 \rightleftharpoons H_2NO_3^

Vedclass · Accepted Answer

Base

Vedclass · Answer

(B) In the nitration of benzene,the reaction between conc. $HNO_3$ and conc. $H_2SO_4$ occurs as follows: $HNO_3 + H_2SO_4 \rightleftharpoons H_2NO_3^+ + HSO_4^-$$H_2NO_3^+ \rightleftharpoons H_2O + NO_2^+$Here,$H_2SO_4$ is a stronger acid than $HNO_3$,so it protonates $HNO_3$. Thus,$HNO_3$ acts as a base in the presence of conc. $H_2SO_4$ to generate the electrophile $NO_2^+$.

Nitrobenzene can be prepared from benzene by using a mixture of conc. $HNO_3$ and conc. $H_2SO_4$. In the nitrating mixture,$HNO_3$ acts as a

Similar Questions

Which of the following compounds is not aromatic?

The species responsible for nitration and sulphonation by nitric acid/conc. $H_2SO_4$ and fuming $H_2SO_4$ are :

Determine the number of aromatic species among the given compounds:

The compound that is most reactive towards electrophilic nitration is

What are the necessary conditions for any system to be aromatic?

Vedclass Test Series

Exam Paper Generator

Online Exam Module