Nitrogen forms $N_2$,but phosphorus forms $P_2$,which quickly converts into $P_4$. The reason for this is:

  • A
    Triple bond present between phosphorus atoms
  • B
    $p\pi - p\pi$ bonding is weak
  • C
    $p\pi - p\pi$ bonding is strong
  • D
    Multiple bond form easily

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Similar Questions

Find the correct statements related to group $15$ hydrides.
$A$. Reducing nature increases from $NH_3$ to $BiH_3$
$B$. Tendency to donate lone pair of electrons decreases from $NH_3$ to $BiH_3$
$C$. The stability of hydrides decreases from $NH_3$ to $BiH_3$
$D$. $HEH$ bond angle decreases from $NH_3$ to $SbH_3$ ($E$ = Elements of group $15$)
Choose the correct answer from the options given below:

Which gas is used in the manufacturing of nitrogenous fertilizers?

Which reaction$(s)$ among the following produce dinitrogen?
$1. NH_4Cl(aq) + NaNO_2(aq) \longrightarrow$
$2. NH_2CONH_2 + 2H_2O \longrightarrow$
$3. Ba(N_3)_2 \longrightarrow$
$4. NH_4Cl + Ca(OH)_2 \longrightarrow$

Which of the following statements is incorrect for nitrogen?

The element that forms stable compounds in low oxidation state is

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