The number of pi electrons in the following m | vedclass

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(D) The given molecule is pyrrole.In pyrrole,there are two double bonds,which contribute $2 	imes 2 = 4$ $\pi$ electrons.The nitrogen atom has a lone

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$6$

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(D) The given molecule is pyrrole.In pyrrole,there are two double bonds,which contribute $2 	imes 2 = 4$ $\pi$ electrons.The nitrogen atom has a lone pair of electrons that participates in resonance to make the ring aromatic.Thus,the lone pair on the nitrogen atom also contributes $2$ $\pi$ electrons.Total number of $\pi$ electrons = $4$ (from double bonds) + $2$ (from lone pair) = $6$ $\pi$ electrons.

The number of $\pi$ electrons in the following molecule is:

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