The number of molecules in a closed container is doubled. What will be the effect on $v_{rms}$?

(NO CHANGE) The root mean square speed $(v_{rms})$ of gas molecules is given by the formula $v_{rms} = \sqrt{\frac{3RT}{M}}$ or $v_{rms} = \sqrt{\frac{3kT}{m}}$.
Here,$R$ is the universal gas constant,$T$ is the absolute temperature,$M$ is the molar mass,$k$ is the Boltzmann constant,and $m$ is the mass of one molecule.
Since $v_{rms}$ depends only on the temperature of the gas and the mass of the molecules,it is independent of the number of molecules or the pressure/volume of the gas.
Therefore,there will be no change in $v_{rms}$.