Xenon tetrafluoride,XeF_4 is: | vedclass

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Question

(B) The structure of $XeF_4$ is square planar due to the presence of two lone pairs on the central $Xe$ atom,which occupy the axial positions to minim

Vedclass · Accepted Answer

$B$. Square planar and acts as a fluoride donor with $PF_5$

Vedclass · Answer

(B) The structure of $XeF_4$ is square planar due to the presence of two lone pairs on the central $Xe$ atom,which occupy the axial positions to minimize repulsion.$XeF_4$ acts as a fluoride donor when it reacts with strong Lewis acids like $SbF_5$,$PF_5$,or $AsF_5$ to form $[XeF_3]^+$ and $[MF_6]^-$ ions.Specifically,$XeF_4 + SbF_5 \rightarrow [XeF_3]^+[SbF_6]^-$.Among the given options,$B$ correctly identifies the geometry as square planar and the property of acting as a fluoride donor with Lewis acids like $PF_5$.

Xenon tetrafluoride,$XeF_4$ is:

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