Number of $sp$ hybridised carbon atoms in the given compound $CH_2=CH-C\equiv C-CH_2-CN$ is:

  • A
    $1$
  • B
    $2$
  • C
    $3$
  • D
    $4$

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Similar Questions

The lone pair of electrons in the given carbanion, $CH_{3}C\equiv C^{-}$, is present in which of the following orbitals?

Which of the following represents the given mode of hybridization $sp^2 - sp^2 - sp - sp$ from left to right?

In the molecule $HC \equiv C - CH_2 - CH = CH - CH_3$,what is the type of hybridization for the $C_2 - C_3$ bond?

Match the following lists:
List-$I$List-$II$
$A$. Ethane$1$. $2 \ sp$ carbons
$B$. Ethylene$2$. $6 \ sp^2$ carbons
$C$. Acetylene$3$. $2 \ sp^3$ carbons
$D$. Benzene$4$. $2 \ sp^2$ carbons
$5$. $1 \ sp$ and $1 \ sp^2$ carbons

What is the type of hybridisation of each carbon atom in the following compounds?
$(a)$ $CH_{3}Cl$
$(b)$ $(CH_{3})_{2}CO$
$(c)$ $CH_{3}CN$
$(d)$ $HCONH_{2}$
$(e)$ $CH_{3}CH=CHCN$

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