Number of pi bonds in CH_2=CH-CH=CH-Cequiv CH | vedclass

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(C) $	ext{Nature of bond}$$	ext{Number of sigma and } \pi 	ext{ bonds}$$	ext{Single bond}$$1 \sigma, 0 \pi$$	ext{Double bond}$$1 \sigma, 1 \pi$$\

Vedclass · Accepted Answer

$4$

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(C) $	ext{Nature of bond}$$	ext{Number of sigma and } \pi 	ext{ bonds}$$	ext{Single bond}$$1 \sigma, 0 \pi$$	ext{Double bond}$$1 \sigma, 1 \pi$$	ext{Triple bond}$$1 \sigma, 2 \pi$In the given compound $CH_2=CH-CH=CH-C\equiv CH$:There are two double bonds,each containing $1 \pi$ bond ($2 	imes 1 = 2 \pi$ bonds).There is one triple bond,which contains $2 \pi$ bonds ($1 	imes 2 = 2 \pi$ bonds).Total number of $\pi$ bonds = $2 + 2 = 4$.

Number of $\pi$ bonds in $CH_2=CH-CH=CH-C\equiv CH$ is

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