Number of electrons flowing per second in a c | vedclass

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(B) Given that,electric current,$I = 9 \,A$.Let $n$ be the number of electrons passing through a conductor in time $t$.We know that,$I = \frac{q}{t}$

Vedclass · Accepted Answer

$5.6 	imes 10^{19}$

Vedclass · Answer

(B) Given that,electric current,$I = 9 \,A$.Let $n$ be the number of electrons passing through a conductor in time $t$.We know that,$I = \frac{q}{t}$ and $q = ne$.Therefore,$I = \frac{ne}{t}$.Rearranging for the number of electrons per second,we get $\frac{n}{t} = \frac{I}{e}$.Substituting the values,where $e = 1.6 	imes 10^{-19} \,C$:$\frac{n}{t} = \frac{9}{1.6 	imes 10^{-19}} = 5.625 	imes 10^{19} \approx 5.6 	imes 10^{19}$ electrons per second.

Number of electrons flowing per second in a conductor carrying a current of $9 \,A$ is

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