Number of letters skipped in between adjacent | vedclass

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(B) To solve this,we analyze the gap between consecutive letters in each option starting from the end (right to left).$1$. For option $A$ $(OIGDC)$: T

Vedclass · Accepted Answer

$OMJFA$

Vedclass · Answer

(B) To solve this,we analyze the gap between consecutive letters in each option starting from the end (right to left).$1$. For option $A$ $(OIGDC)$: The sequence is $C, D, G, I, O$. The gaps are: $C$ to $D$ ($0$ letters),$D$ to $G$ ($2$ letters: $E, F$),$G$ to $I$ ($1$ letter: $H$),$I$ to $O$ ($5$ letters). This does not follow a consistent pattern.$2$. For option $B$ $(OMJFA)$: The sequence is $A, F, J, M, O$. The gaps are: $A$ to $F$ ($4$ letters: $B, C, D, E$),$F$ to $J$ ($3$ letters: $G, H, I$),$J$ to $M$ ($2$ letters: $K, L$),$M$ to $O$ ($1$ letter: $N$).$3$. The gaps are $4, 3, 2, 1$. This means the number of letters skipped decreases by $1$ as we move from right to left,or increases by $1$ as we move from left to right. This matches the rule.

Number of letters skipped in between adjacent letters of the series starting from behind are increased by one. Which of the following series observes this rule?

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Number of letters skipped in between adjacent letters of the series starting from behind are increased by one. Which of the following series observes this rule?

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