Number of possible isomers for [Cr(H_2O)_2(C_ | vedclass

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Question

(A) The complex $[Cr(H_2O)_2(C_2O_4)_2]^{-}$ is an octahedral complex of the type $[M(AA)_2(a)_2]$.Here,$AA$ represents the bidentate oxalate ligand $

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(A) The complex $[Cr(H_2O)_2(C_2O_4)_2]^{-}$ is an octahedral complex of the type $[M(AA)_2(a)_2]$.Here,$AA$ represents the bidentate oxalate ligand $(C_2O_4^{2-})$ and $a$ represents the monodentate aqua ligand $(H_2O)$.This type of complex exhibits geometric isomerism:$1$. $cis$-isomer: The two $H_2O$ ligands are adjacent to each other. The $cis$-isomer is optically active and exists as a pair of enantiomers ($d$ and $l$ forms).$2$. $trans$-isomer: The two $H_2O$ ligands are opposite to each other. The $trans$-isomer is optically inactive due to the presence of a plane of symmetry.Therefore,the total number of isomers is $3$ ($cis$-$d$,$cis$-$l$,and $trans$).

Number of possible isomers for $[Cr(H_2O)_2(C_2O_4)_2]^{-}$ are . . . . . . .

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