Obtain approximately the ratio of the nuclear radii of the gold isotope $^{197}_{79}Au$ and the silver isotope $^{107}_{47}Ag$.

(N/A) The nuclear radius $R$ of a nucleus with mass number $A$ is given by the formula $R = R_0 A^{1/3}$,where $R_0$ is a constant.
For the gold isotope $^{197}_{79}Au$,the mass number $A_{Au} = 197$.
For the silver isotope $^{107}_{47}Ag$,the mass number $A_{Ag} = 107$.
The ratio of the nuclear radii is given by:
$\frac{R_{Au}}{R_{Ag}} = \left( \frac{A_{Au}}{A_{Ag}} \right)^{1/3} = \left( \frac{197}{107} \right)^{1/3}$.
Calculating the value:
$\frac{197}{107} \approx 1.841$.
$(1.841)^{1/3} \approx 1.2256$.
Rounding to two decimal places,the ratio is approximately $1.23$.