Obtain the binding energy of the nuclei $^{56}_{26} Fe$ and $^{209}_{83} Bi$ in units of $MeV$ from the following data:
$m(^{56}_{26} Fe) = 55.934939 \; u$
$m(^{209}_{83} Bi) = 208.980388 \; u$ (in $; MeV$)

If the binding energy of $N^{14}$ is $7.5 \text{ MeV}$ per nucleon and that of $N^{15}$ is $7.7 \text{ MeV}$ per nucleon, then the energy required to remove a neutron from $N^{15}$ is (in $\text{ MeV}$)

The binding energy per nucleon $v/s$ mass number curve for nuclei is shown in the figure. $w, x, y$ and $z$ are four nuclei indicated on the curve. The process that would release energy is:

$A$ heavy nucleus having mass number $200$ gets disintegrated into two small fragments of mass numbers $80$ and $120$. If binding energy per nucleon for the parent atom is $6.5 \text{ MeV}$ and for the daughter nuclei is $7 \text{ MeV}$ and $8 \text{ MeV}$ respectively, then the energy released in the decay will be: (in $\text{ MeV}$)

For which mass number range is the binding energy per nucleon maximum?

The binding energy per nucleon of ${O^{16}}$ is $7.97 \,MeV$ and that of ${O^{17}}$ is $7.75 \,MeV$. The energy (in $MeV$) required to remove a neutron from ${O^{17}}$ is