Of three numbers,the second is thrice the fir | vedclass

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(B) Let the first number be $x$.Then,the second number $= 3x$ and the third number $= \frac{3x}{4}$.The average of the three numbers is given as $114$

Vedclass · Accepted Answer

$216$

Vedclass · Answer

(B) Let the first number be $x$.Then,the second number $= 3x$ and the third number $= \frac{3x}{4}$.The average of the three numbers is given as $114$,so their sum is $3 	imes 114 = 342$.According to the problem:$x + 3x + \frac{3x}{4} = 342$Multiply the entire equation by $4$ to clear the fraction:$4x + 12x + 3x = 342 	imes 4$$19x = 1368$Solving for $x$:$x = \frac{1368}{19} = 72$The three numbers are:First number $= 72$Second number $= 3 	imes 72 = 216$Third number $= \frac{3 	imes 72}{4} = 3 	imes 18 = 54$Comparing the three numbers $(72, 216, 54)$,the largest number is $216$.

Of three numbers,the second is thrice the first and the third number is three-fourths of the first. If the average of the three numbers is $114$,the largest number is

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