On a dry road,the maximum speed of a vehicle | vedclass

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(B) The maximum safe speed $V$ of a vehicle on a circular road of radius $r$ is given by $V = \sqrt{\mu rg}$,where $\mu$ is the coefficient of frictio

Vedclass · Accepted Answer

$\frac{\mu}{4}$

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(B) The maximum safe speed $V$ of a vehicle on a circular road of radius $r$ is given by $V = \sqrt{\mu rg}$,where $\mu$ is the coefficient of friction.For the dry road: $V = \sqrt{\mu rg}$ $(i)$For the wet road,let the new coefficient of friction be $\mu^{\prime}$. The new speed is $\frac{V}{2} = \sqrt{\mu^{\prime} rg}$ (ii)Dividing equation $(i)$ by equation (ii):$\frac{V}{V/2} = \frac{\sqrt{\mu rg}}{\sqrt{\mu^{\prime} rg}}$$2 = \sqrt{\frac{\mu}{\mu^{\prime}}}$Squaring both sides:$4 = \frac{\mu}{\mu^{\prime}}$$	herefore \mu^{\prime} = \frac{\mu}{4}$

On a dry road,the maximum speed of a vehicle along a circular path is $V$. When the road becomes wet,the maximum speed becomes $\frac{V}{2}$. If the coefficient of friction of the dry road is $\mu$,then the coefficient of friction of the wet road is:

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