On adding AgNO_3 solution into KI solution,a | vedclass

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(D) The reaction is $AgNO_3 + KI \rightarrow AgI (s) + KNO_3$. For a negatively charged colloidal sol of $AgI$,the dispersion medium must contain an e

Vedclass · Accepted Answer

$100 \ mL$ of $0.1 \ M \ AgNO_3 + 100 \ mL$ of $0.15 \ M \ KI$

Vedclass · Answer

(D) The reaction is $AgNO_3 + KI ightarrow AgI (s) + KNO_3$. For a negatively charged colloidal sol of $AgI$,the dispersion medium must contain an excess of $I^-$ ions,which are adsorbed on the surface of $AgI$ particles. This occurs when the number of millimoles of $KI$ is greater than the number of millimoles of $AgNO_3$. In option $D$,millimoles of $KI = 100 \ mL 	imes 0.15 \ M = 15 \ mmol$ and millimoles of $AgNO_3 = 100 \ mL 	imes 0.1 \ M = 10 \ mmol$. Since $15 > 10$,$KI$ is in excess,resulting in a negatively charged sol.

On adding $AgNO_3$ solution into $KI$ solution,a negatively charged colloidal sol is obtained when they are in:

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