On adding a solute to a solvent having a vapour pressure of $0.80 \ atm$,the vapour pressure reduces to $0.60 \ atm$. The mole fraction of the solute is:

$A$ solution contains $KCl$ in water. It is heated continuously and the vapour formed is removed continuously. The vapour pressure of the solution will be:

The vapour pressure of two liquids $P$ and $Q$ are $80$ and $60 \, torr$,respectively. The total vapour pressure of the solution obtained by mixing $3 \, mole$ of $P$ and $2 \, mole$ of $Q$ would be .......... $torr$.

Vapour pressure of $CCl_4$ at $25 \text{ }^\circ\text{C}$ is $143 \text{ mm Hg}$. If $0.5 \text{ g}$ of a non-volatile solute is dissolved in $100 \text{ cm}^3$ of $CCl_4$, find the vapour pressure of the solution. (Density of $CCl_4 = 1.58 \text{ g/cm}^3$ and molar mass of solute = $65 \text{ g/mol}$) (in $\text{ mm Hg}$)

If vapour pressure of pure solvent and solution are $240 \ mm Hg$ and $216 \ mm Hg$ respectively,then the mole fraction of solvent in the solution is:

At $T \ K$,the vapour pressure of water is $x \ kPa$. What is the vapour pressure (in $kPa$) of a $1 \ m$ (molal) aqueous solution containing a non-volatile solute (in $x$)?