On dividing a number by $56$,we get $29$ as remainder. On dividing the same number by $8$,what will be the remainder?

The sum of five consecutive even numbers of set $A$ is $220$. What is the sum of a different set of five consecutive numbers whose second lowest number is $37$ less than double of the lowest number of set $A$?

The product of two numbers is $1575$ and their quotient is $\frac{9}{7}$. Then the sum of the numbers is

$(13.96)^{2} - (15.03)^{2} + (18.09)^{2} - 32.65 = ?$

$(21.5 \% \text{ of } 999)^{1/3} + (42 \% \text{ of } 601)^{1/2} + ? = 28$ (Assuming the equation equals $28$ for a standard evaluation)

If doubling a number and adding $20$ to the result gives the same answer as multiplying the number by $8$ and taking away $4$ from the product,the number is