On each side of a polygon of n sides,a capaci | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) polygon with $n$ sides has $n$ capacitors. One capacitor is placed directly between points $A$ and $B$.The remaining $(n - 1)$ capacitors are conn

Vedclass · Accepted Answer

$\frac{nC}{n - 1}$

Vedclass · Answer

(B) polygon with $n$ sides has $n$ capacitors. One capacitor is placed directly between points $A$ and $B$.The remaining $(n - 1)$ capacitors are connected in series along the other path between $A$ and $B$.The equivalent capacitance of these $(n - 1)$ capacitors in series is given by:$C_{series} = \frac{C}{n - 1}$Now,this equivalent capacitor is in parallel with the single capacitor $C$ connected directly between $A$ and $B$.The total equivalent capacitance $C_{eq}$ is:$C_{eq} = C + C_{series} = C + \frac{C}{n - 1}$$C_{eq} = \frac{C(n - 1) + C}{n - 1} = \frac{Cn - C + C}{n - 1} = \frac{nC}{n - 1}$

On each side of a polygon of $n$ sides,a capacitor of capacitance $C$ is placed as shown in the figure. The equivalent capacitance across $A$ and $B$ is:

Similar Questions

Three capacitors of capacitance $3\,\mu F$ are connected in a circuit. Then their maximum and minimum capacitances will be

Four capacitors are connected as shown in the adjoining figure. The capacitance of each is $8\,\mu F$. The equivalent capacitance between the points $A$ and $B$ will be......$\mu F$.

Four identical capacitors are connected in series with a battery of $emf$ $10 \ V$. Point $X$ is grounded. Find the potential at point $A$ in $V$.

The equivalent capacitance between the points $A$ and $B$ of the network shown in the figure is (in $\text{ F}$)

Two capacitors each having a capacitance $2 \times 10^{-6} \ F$ and a breakdown voltage $5000 \ V$,are joined in series. What will be the resultant capacitance and the breakdown voltage of the combination?

Vedclass Test Series

Exam Paper Generator

Online Exam Module