On heating,compound (A) gives a gas (B) which | vedclass

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(B) The basic gas $(C)$ is ammonia $(NH_{3})$.According to the Haber process,$N_{2} + 3H_{2} \rightleftharpoons 2NH_{3}$. Thus,gas $(B)$ must be $N_{2

Vedclass · Accepted Answer

$Pb(NO_{3})_{2}$

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(B) The basic gas $(C)$ is ammonia $(NH_{3})$.According to the Haber process,$N_{2} + 3H_{2} \rightleftharpoons 2NH_{3}$. Thus,gas $(B)$ must be $N_{2}$.Let us analyze the thermal decomposition of the given compounds:$(1)$ $(NH_{4})_{2}Cr_{2}O_{7} \xrightarrow{\Delta} N_{2} \uparrow + Cr_{2}O_{3} + 4H_{2}O \uparrow$ (Produces $N_{2}$)$(2)$ $Pb(NO_{3})_{2} \xrightarrow{\Delta} PbO + 2NO_{2} \uparrow + \frac{1}{2}O_{2} \uparrow$ (Does not produce $N_{2}$)$(3)$ $2NaN_{3} \xrightarrow{\Delta} 2Na + 3N_{2} \uparrow$ (Produces $N_{2}$)$(4)$ $NH_{4}NO_{2} \xrightarrow{\Delta} N_{2} \uparrow + 2H_{2}O \uparrow$ (Produces $N_{2}$)Since $(A)$ must produce $N_{2}$ gas,$(A)$ cannot be $Pb(NO_{3})_{2}$.

On heating,compound $(A)$ gives a gas $(B)$ which is a constituent of air. This gas,when treated with $H_{2}$ in the presence of a catalyst,gives another gas $(C)$ which is basic in nature. $(A)$ should not be:

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