On hydrolysis,(Me)_2SiCl_2 will produce: | vedclass

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(C) The hydrolysis of dimethyldichlorosilane,$(Me)_2SiCl_2$,proceeds as follows:$1$. First,the chlorine atoms are replaced by hydroxyl groups to form

Vedclass · Accepted Answer

$-[-O-Si(Me)_2-O-]_n-$

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(C) The hydrolysis of dimethyldichlorosilane,$(Me)_2SiCl_2$,proceeds as follows:$1$. First,the chlorine atoms are replaced by hydroxyl groups to form the unstable intermediate $(Me)_2Si(OH)_2$.$2$. This intermediate undergoes rapid condensation polymerization by eliminating water molecules to form a linear silicone polymer.$3$. The reaction is represented as: $n(Me)_2SiCl_2 + 2nH_2O \rightarrow [-O-Si(Me)_2-O-]_n + 2nHCl$.$4$. Thus,the final product is a linear silicone polymer,represented by option $(C)$.

On hydrolysis,$(Me)_2SiCl_2$ will produce:

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