On treating SO_2 with an aqueous solution of | vedclass

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(A) The reaction between $KMnO_4$ and $SO_2$ in an aqueous medium is a redox reaction where $KMnO_4$ acts as an oxidizing agent and $SO_2$ acts as a r

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$Mn^{2+}$ only

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(A) The reaction between $KMnO_4$ and $SO_2$ in an aqueous medium is a redox reaction where $KMnO_4$ acts as an oxidizing agent and $SO_2$ acts as a reducing agent.The balanced chemical equation for this reaction is:$2KMnO_4 + 5SO_2 + 2H_2O \rightarrow K_2SO_4 + 2MnSO_4 + 2H_2SO_4$In this reaction,the oxidation state of manganese changes from $+7$ in $KMnO_4$ to $+2$ in $MnSO_4$.Therefore,the manganese ion reduces to $Mn^{2+}$ only.

On treating $SO_2$ with an aqueous solution of $KMnO_4$,the manganese ion reduces to

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