One mole each of urea,glucose,and sodium chlo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Osmotic pressure $(\pi)$ is a colligative property,which depends on the number of particles in the solution. $\pi = iCRT$,where $i$ is the van't H

Vedclass · Accepted Answer

Urea and glucose

Vedclass · Answer

(B) Osmotic pressure $(\pi)$ is a colligative property,which depends on the number of particles in the solution. $\pi = iCRT$,where $i$ is the van't Hoff factor. For urea $(NH_2CONH_2)$ and glucose $(C_6H_{12}O_6)$,both are non-electrolytes,so $i = 1$. For sodium chloride $(NaCl)$,it ionizes as $NaCl \rightarrow Na^+ + Cl^-$,so $i = 2$. Since urea and glucose have the same van't Hoff factor $(i = 1)$ and the same concentration $(C)$,they will produce equal osmotic pressure.

One mole each of urea,glucose,and sodium chloride were dissolved in one litre of water. Equal osmotic pressure will be produced by solutions of

Similar Questions

$A$ semipermeable membrane is that which permits the passage of:

Calculate the osmotic pressure of a $0.2 \ M$ aqueous solution of an electrolyte at $300 \ K$. If the van't Hoff factor is $1.6$,find the osmotic pressure. $\left[R=0.0821 \ atm \ dm^3 \ K^{-1} \ mol^{-1}\right]$ (in $atm$)

Arrange the following equimolar solutions according to increasing order of osmotic pressure [Assume complete ionisation]:
$A$. $KCl$
$B$. $BaCl_2$
$C$. $AlCl_3$
$D$. $Al_2(SO_4)_3$

The osmotic pressure of a $5\%$ solution of cane sugar at $150\,^{\circ}C$ is ......... $atm$. (mol. wt. of cane sugar $= 342$)

Identify the pair of solutions that exhibits the same osmotic pressure. [Molar mass of urea $= 60 \text{ g mol}^{-1}$ and molar mass of glucose $= 180 \text{ g mol}^{-1}$]

Vedclass Test Series

Exam Paper Generator

Online Exam Module