(B) The equilibrium constant $K_C$ for the reaction $A_{(g)} \rightleftharpoons B_{(g)}$ is given by $K_C = \frac{[B]}{[A]} = 10^{-1}$.Since the tempe

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(B) The equilibrium constant $K_C$ for the reaction $A_{(g)} \rightleftharpoons B_{(g)}$ is given by $K_C = \frac{[B]}{[A]} = 10^{-1}$.Since the temperature remains constant,the value of the equilibrium constant $K_C$ remains unchanged regardless of the addition of reactants or products.Therefore,at the new equilibrium state,the ratio $\frac{[B]}{[A]}$ will still be equal to $10^{-1}$.Consequently,the value of $\frac{[A]}{[B]} = \frac{1}{K_C} = \frac{1}{10^{-1}} = 10$.

Class 11 Chemistry 1 Equilibrium: Chemical Equilibrium Kp and Kc Relationship

Easy

One mole of $A_{(g)}$ is heated to $T(K)$ until the following equilibrium is obtained:
$A_{(g)} \rightleftharpoons B_{(g)}$
The equilibrium constant of this reaction is $10^{-1}$. After reaching the equilibrium,$0.5 \ mol$ of $A_{(g)}$ is added and heated. The equilibrium is again established. The value of $\frac{[A]}{[B]}$ is:

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A
$10^{-1}$
B
$10$
C
$10^{-2}$
D
$100$

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1 Equilibrium: Chemical Equilibrium

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Kp and Kc Relationship

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$A_{(s)} \rightleftharpoons M_{(s)} + \frac{1}{2} O_{2(g)}$
The equilibrium constant for the reaction is $K_{p} = 4$. At equilibrium,the partial pressure of $O_{2}$ is $.... \ atm.$ (Round off to the nearest integer).

MediumJEE MAIN 2021

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For the reversible reaction in equilibrium:
$N_{2(g)} + O_{2(g)} \underset{k_2}{\overset{k_1}{\longleftrightarrow}} 2NO_{(g)}$
Given $C_0 = C e^{-2.1 \times 10^{-3}t}$ for the forward reaction and $C'_0 = C' e^{-4.2 \times 10^{-4}t}$ for the backward reaction,calculate the equilibrium constant $K_c$ for the above reaction.

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The equilibrium constant of $NH_4COONH_2$ in a closed vessel at $400 \ K$ temperature is $600 \ bar^3$. What will be the total pressure at equilibrium (in $bar$)?
$NH_4COONH_{2(s)} \rightleftharpoons 2NH_{3(g)} + CO_{2(g)}$

Medium

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At $1000 \ K$,the partial pressures of $CO_{2(g)}$ and $CO_{(g)}$ for the reaction $CO_{2(g)} + C_{(s)} \rightleftharpoons 2 CO_{(g)}$ in a closed vessel at equilibrium are $0.15 \ bar$ and $0.60 \ bar$ respectively. The $K_c$ for this reaction at the same temperature is approximately

DifficultAP EAMCET 2019

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For the reaction $PCl_5 \rightleftharpoons PCl_3 + Cl_2$,at equilibrium,the number of moles of $PCl_5$,$PCl_3$,and $Cl_2$ are $2 \ mol$ each,and the total pressure is $3 \ atm$. What is the value of $K_p$ in $atm$?

Medium

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$A_{(s)} \rightleftharpoons M_{(s)} + \frac{1}{2} O_{2(g)}$The equilibrium constant for the reaction is $K_{p} = 4$. At equilibrium,the partial pressure of $O_{2}$ is $.... \ atm.$ (Round off to the nearest integer).

The equilibrium constant of $NH_4COONH_2$ in a closed vessel at $400 \ K$ temperature is $600 \ bar^3$. What will be the total pressure at equilibrium (in $bar$)?$NH_4COONH_{2(s)} \rightleftharpoons 2NH_{3(g)} + CO_{2(g)}$

At $1000 \ K$,the partial pressures of $CO_{2(g)}$ and $CO_{(g)}$ for the reaction $CO_{2(g)} + C_{(s)} \rightleftharpoons 2 CO_{(g)}$ in a closed vessel at equilibrium are $0.15 \ bar$ and $0.60 \ bar$ respectively. The $K_c$ for this reaction at the same temperature is approximately

For the reaction $PCl_5 \rightleftharpoons PCl_3 + Cl_2$,at equilibrium,the number of moles of $PCl_5$,$PCl_3$,and $Cl_2$ are $2 \ mol$ each,and the total pressure is $3 \ atm$. What is the value of $K_p$ in $atm$?

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$A_{(s)} \rightleftharpoons M_{(s)} + \frac{1}{2} O_{2(g)}$
The equilibrium constant for the reaction is $K_{p} = 4$. At equilibrium,the partial pressure of $O_{2}$ is $.... \ atm.$ (Round off to the nearest integer).

The equilibrium constant of $NH_4COONH_2$ in a closed vessel at $400 \ K$ temperature is $600 \ bar^3$. What will be the total pressure at equilibrium (in $bar$)?
$NH_4COONH_{2(s)} \rightleftharpoons 2NH_{3(g)} + CO_{2(g)}$