One mole of a symmetrical alkene on ozonolysi | vedclass

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(C) Ozonolysis of a symmetrical alkene $R-CH=CH-R$ yields two moles of the same aldehyde $R-CHO$.The molecular mass of the aldehyde is $44 \ u$.The ge

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$2$-butene

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(C) Ozonolysis of a symmetrical alkene $R-CH=CH-R$ yields two moles of the same aldehyde $R-CHO$.The molecular mass of the aldehyde is $44 \ u$.The general formula for an aldehyde is $C_nH_{2n}O$.$12n + 2n + 16 = 44 \implies 14n = 28 \implies n = 2$.Thus,the aldehyde is acetaldehyde $(CH_3CHO)$.The reaction is: $CH_3-CH=CH-CH_3 \xrightarrow{O_3, Zn/H_2O} 2CH_3CHO$.Therefore,the symmetrical alkene is $2$-butene.

One mole of a symmetrical alkene on ozonolysis gives two moles of an aldehyde having a molecular mass of $44 \ u$. The alkene is

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