One mole of the complex compound Co(NH_3)_5Cl | vedclass

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(A) The reaction of the complex with $AgNO_3$ to yield $2$ moles of $AgCl_{(s)}$ indicates that there are $2$ chloride ions $(Cl^-)$ present outside t

Vedclass · Accepted Answer

$[Co(NH_3)_5Cl]Cl_2$

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(A) The reaction of the complex with $AgNO_3$ to yield $2$ moles of $AgCl_{(s)}$ indicates that there are $2$ chloride ions $(Cl^-)$ present outside the coordination sphere (ionizable chloride ions).When $[Co(NH_3)_5Cl]Cl_2$ dissolves in water,it dissociates as follows:$[Co(NH_3)_5Cl]Cl_2 \rightarrow [Co(NH_3)_5Cl]^{2+} + 2Cl^-$This results in a total of $1 + 2 = 3$ moles of ions per mole of the complex,which matches the given information.Therefore,the correct structure is $[Co(NH_3)_5Cl]Cl_2$.

One mole of the complex compound $Co(NH_3)_5Cl_3$ gives $3$ moles of ions on dissolution in water. One mole of the same complex reacts with two moles of $AgNO_3$ solution to yield two moles of $AgCl_{(s)}$. The structure of the complex is :-

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