One mole of the octahedral complex compound C | vedclass

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(A) The complex $Co(NH_3)_5Cl_3$ dissociates in water to give $3$ moles of ions,which implies the formula is $[Co(NH_3)_5Cl]Cl_2$. The dissociation re

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$[Co(NH_3)_5Cl]Cl_2$

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(A) The complex $Co(NH_3)_5Cl_3$ dissociates in water to give $3$ moles of ions,which implies the formula is $[Co(NH_3)_5Cl]Cl_2$. The dissociation reaction is: $[Co(NH_3)_5Cl]Cl_2 \rightarrow [Co(NH_3)_5Cl]^{2+} + 2Cl^{-}$. This results in $1$ complex ion and $2$ chloride ions,totaling $3$ ions. The reaction with excess $AgNO_3$ confirms the presence of $2$ ionizable chloride ions: $[Co(NH_3)_5Cl]Cl_2 + 2AgNO_3 \rightarrow [Co(NH_3)_5Cl](NO_3)_2 + 2AgCl_{(s)}$.

One mole of the octahedral complex compound $Co(NH_3)_5Cl_3$ gives $3$ moles of ions on dissolution in water. One mole of the same complex reacts with excess of $AgNO_3$ solution to yield two moles of $AgCl_{(s)}$. The structure of the complex is :

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