One of the factors of ldots ldots ldots ldots | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to the Factor Theorem,if $(x-a)$ is a factor of a polynomial $p(x)$,then $p(a) = 0$.Here,the given factor is $(x-1)$,so we must have $p(

Vedclass · Accepted Answer

$p(x)=x^{2}+2x-3$

Vedclass · Answer

(A) According to the Factor Theorem,if $(x-a)$ is a factor of a polynomial $p(x)$,then $p(a) = 0$.Here,the given factor is $(x-1)$,so we must have $p(1) = 0$.Let us check each option:$A) p(1) = (1)^{2} + 2(1) - 3 = 1 + 2 - 3 = 0$. Since $p(1) = 0$,$(x-1)$ is a factor.$B) p(1) = (1)^{2} + 4(1) + 3 = 1 + 4 + 3 = 8 
eq 0$.$C) p(1) = (1)^{2} + 5(1) + 6 = 1 + 5 + 6 = 12 
eq 0$.$D) p(1) = (1)^{2} + (1) - 6 = 1 + 1 - 6 = -4 
eq 0$.Therefore,the correct option is $A$.

One of the factors of $\ldots \ldots \ldots \ldots$ is $(x-1).$

Similar Questions

If the product of the zeros of $p(x) = ax^{2} - 6x - 6$ is $4$,then $a = $ ............

If the zero of the polynomial $p(x) = 3x^{3} - x^{2} - ax - 45$ is $3$,then $a = \dots$

Is the following statement True or False? Justify your answer. If the zeroes of a quadratic polynomial $ax^2 + bx + c$ are both negative,then $a, b,$ and $c$ all have the same sign.

The zeros of the cubic polynomial $p(x) = ax^3 + bx^2 + cx + d$ where $a \neq 0$ and $a, b, c, d \in R$ are $\alpha, \beta,$ and $\gamma$. Then $\alpha \beta \gamma = \dots$

The zeros of the quadratic polynomial $p(x) = 3x^2 + 5x - 8$ are $\ldots \ldots \ldots \ldots$

Vedclass Test Series

Exam Paper Generator

Online Exam Module