(C) Given the quadratic equation: $(x-3)^{2}-4=0$We can rewrite this as: $(x-3)^{2}=4$Taking the square root on both sides,we get: $x-3 = \pm \sqrt{4}

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(C) Given the quadratic equation: $(x-3)^{2}-4=0$We can rewrite this as: $(x-3)^{2}=4$Taking the square root on both sides,we get: $x-3 = \pm \sqrt{4}$$x-3 = \pm 2$This gives two possible cases:Case $1$: $x-3 = 2 \implies x = 2+3 = 5$Case $2$: $x-3 = -2 \implies x = -2+3 = 1$The solutions are $x=5$ and $x=1$.Comparing this with the given options,$1$ is one of the solutions.

Class 10 Mathematics Quadratic Equations Solution of a Quadratic Equation by Factorisation

Medium

One of the solutions of the quadratic equation $(x-3)^{2}-4=0$ is ..... .

A
$3$
B
$4$
C
$1$
D
$-1$

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Quadratic Equations

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Solution of a Quadratic Equation by Factorisation

Solve the following equation using the method of factorization and write its solution set: $\frac{x+1}{x+2} + \frac{1}{x} = \frac{5}{4}$

Medium

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Factorize the following polynomial: $p(x) = x^{2} + 5x - 24$

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Solve the following equation using the method of factorization and write its solution set: $\frac{x}{x+1} + \frac{x+1}{x} = \frac{5}{2}$

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Solve the following equation using the method of factorization: $x + 3 + \frac{2}{x} = 0$.

Easy

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The formula to find the sum $S$ of the first $n$ natural numbers is $S = \frac{n(n+1)}{2}$. Find $n$ if the sum of the first $n$ natural numbers is $300$.

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One of the solutions of the quadratic equation $(x-3)^{2}-4=0$ is ..... .

Similar Questions

Solve the following equation using the method of factorization and write its solution set: $\frac{x+1}{x+2} + \frac{1}{x} = \frac{5}{4}$

Factorize the following polynomial: $p(x) = x^{2} + 5x - 24$

Solve the following equation using the method of factorization and write its solution set: $\frac{x}{x+1} + \frac{x+1}{x} = \frac{5}{2}$

Solve the following equation using the method of factorization: $x + 3 + \frac{2}{x} = 0$.

The formula to find the sum $S$ of the first $n$ natural numbers is $S = \frac{n(n+1)}{2}$. Find $n$ if the sum of the first $n$ natural numbers is $300$.

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