Only $4 \%$ of the total current in the circuit passes through a galvanometer. If the resistance of the galvanometer is $G$,then the shunt resistance connected to the galvanometer is

  • A
    $\frac{G}{25}$
  • B
    $\frac{G}{24}$
  • C
    $24 G$
  • D
    $25 G$

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