Only an aldehyde having..... can undergo the aldol condensation.

  • A
    At least one $\beta$ $H$ atom
  • B
    At least one $\alpha$ $H$ atom
  • C
    An aromatic ring
  • D
    No $\alpha$ $H$ atom

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The compound $A$ in the following reaction is:
$A$ $\xrightarrow[(ii) Conc. H_2SO_4 / \Delta]{(i) CH_3MgBr / H_2O} B$ $\xrightarrow[(ii) Zn / H_2O]{(i) O_3} C + D$
$D \xrightarrow[Ba(OH)_2, \Delta]{} CH_3-C(CH_3)=CH-CO-CH_3$

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$\alpha-H$ containing aldehyde and ketone reacts with dil $NaOH$ and gives $\beta-hydroxy$ aldehyde or $\beta-hydroxy$ ketone. This reaction is called $-$

How will you convert butan-$2$-one to propanoic acid?
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Acetaldehyde cannot give:

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