Optical activity of an enantiomeric mixture i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The optical purity of an enantiomeric mixture is calculated using the formula: $	ext{Optical Purity} = \frac{	ext{observed rotation of mixture}}

Vedclass · Accepted Answer

$42$

Vedclass · Answer

(D) The optical purity of an enantiomeric mixture is calculated using the formula: $	ext{Optical Purity} = \frac{	ext{observed rotation of mixture}}{	ext{specific rotation of pure enantiomer}} 	imes 100$. Given: $	ext{Observed rotation} = +12.6^{\circ}$ and $	ext{Specific rotation} = +30^{\circ}$. Substituting the values: $	ext{Optical Purity} = \frac{12.6}{30} 	imes 100 = 0.42 	imes 100 = 42\%$. Thus,the optical purity is $42\%$.

Optical activity of an enantiomeric mixture is $+12.6^{\circ}$ and the specific rotation of the $(+)$ isomer is $+30^{\circ}$. The optical purity is $......... \%$.

Similar Questions

The number of optical isomers of an organic compound having $n$ asymmetric carbon atoms will be

$A$ racemic mixture is formed by mixing which of the following?

Which of the following compounds is an optically active compound?

What is the possible number of optical isomers for a compound containing $2$ dissimilar asymmetric carbon atoms?

Which one of the following exhibits enantiomerism?

Vedclass Test Series

Exam Paper Generator

Online Exam Module