Orbital angular momentum of an electron in 3s | vedclass

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Question

(A) The formula for orbital angular momentum is $\sqrt{\ell(\ell+1)} \frac{h}{2 \pi}$.For a $3s$ subshell,the azimuthal quantum number $\ell = 0$. Thu

Vedclass · Accepted Answer

$0, \frac{h}{\sqrt{2} \pi}$

Vedclass · Answer

(A) The formula for orbital angular momentum is $\sqrt{\ell(\ell+1)} \frac{h}{2 \pi}$.For a $3s$ subshell,the azimuthal quantum number $\ell = 0$. Thus,the orbital angular momentum $= \sqrt{0(0+1)} \frac{h}{2 \pi} = 0$.For a $3p$ subshell,the azimuthal quantum number $\ell = 1$. Thus,the orbital angular momentum $= \sqrt{1(1+1)} \frac{h}{2 \pi} = \sqrt{2} \frac{h}{2 \pi} = \frac{h}{\sqrt{2} \pi}$.

Orbital angular momentum of an electron in $3s$ and $3p$ subshells are:

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