Order of boiling points of the given compound | vedclass

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(A) The boiling point of alcohols depends on the molecular mass and the extent of branching.$1$. As the molecular mass increases,the boiling point inc

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$a > b > c > d$

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(A) The boiling point of alcohols depends on the molecular mass and the extent of branching.$1$. As the molecular mass increases,the boiling point increases. The order of molecular mass is: $	ext{pentan-1-ol} (C_5H_{12}O) > 	ext{butan-1-ol} = 	ext{butan-2-ol} (C_4H_{10}O) > 	ext{propan-1-ol} (C_3H_8O)$.$2$. For isomers with the same molecular mass,the boiling point decreases with an increase in branching because the surface area decreases,leading to weaker van der Waals forces. Thus,$	ext{butan-1-ol}$ (straight chain) has a higher boiling point than $	ext{butan-2-ol}$ (branched).$3$. Combining these factors,the order is: $	ext{pentan-1-ol} (a) > 	ext{butan-1-ol} (b) > 	ext{butan-2-ol} (c) > 	ext{propan-1-ol} (d)$.

Order of boiling points of the given compounds is:
$(a)$ $\text{pentan-1-ol}$
$(b)$ $\text{butan-1-ol}$
$(c)$ $\text{butan-2-ol}$
$(d)$ $\text{propan-1-ol}$

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Order of boiling points of the given compounds is:$(a)$ $\text{pentan-1-ol}$$(b)$ $\text{butan-1-ol}$$(c)$ $\text{butan-2-ol}$$(d)$ $\text{propan-1-ol}$